Hoe To Compere A Function

Uniformly Accelerated Motion (MUA)

A Mobile has a uniformly accelerated motion when the body increases or decreases speed kept pace.
if a = delta v / t, then V = V0 + at
The mobile photo ever experience the same gear.

average acceleration a = v (final) - v (initial) / t = delta v / delta t
the average speed is Vm = v (final) + v (initial) / 2
Space traveled during time t will d = Vm * t

know that d = Vm * t and Vm = (vi + vf) / 2 ie d = (vi + vf) / 2 * t , but
vf = vi + at , then
d = (vi + vi + at) / 2 * t , rearranging: d = (2 vi + at) / 2 * t
being d = (vi * t + t2) / 2
therefore d = vi * t + a / 2 * t2 We

other deduction:
know vf-vi = a * t ; d = Vm * t , then vf-vi = a * (d / Vm) Vm
(vf - vi) = a * d but as Vm = (vf + vi) / 2
then (vf + vi) / 2 * (vf-vi) = a * d , this equation is multiplied by 2
(vf + vi) ( vf-vi) = 2ad
VF2 - VI2 = 2ad if vi = 0, then VF2 = 2ad therefore 2ad vf = Root